ConjugateDiameter Command
- ConjugateDiameter( <Line>, <Conic> )
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Returns the conjugate diameter of the diameter that is parallel to the given line (relative to the conic section).
ConjugateDiameter(-4x + 5y = -2, x^2 + 4 y^2 + 2x - 8y + 1 = 0) yields line 5x + 16y = 11
- ConjugateDiameter( <Vector>, <Conic> )
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Returns the conjugate diameter of the diameter that is parallel to the given vector (relative to the conic section).
Let u = (4,1) be a vector. Then ConjugateDiameter(u, x^2 + 4 y^2 + 2x - 8y + 1 = 0) yields line x + y = 0